x^2+1060x-93800=0

Solution for x^2+1060x-93800=0 equation:

x^2+1060x-93800=0

a = 1; b = 1060; c = -93800;
Δ = b2-4ac
Δ = 10602-4·1·(-93800)
Δ = 1498800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1498800}=\sqrt{400*3747}=\sqrt{400}*\sqrt{3747}=20\sqrt{3747}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1060)-20\sqrt{3747}}{2*1}=\frac{-1060-20\sqrt{3747}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1060)+20\sqrt{3747}}{2*1}=\frac{-1060+20\sqrt{3747}}{2}
$